If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x^2+23x=-12
We move all terms to the left:
10x^2+23x-(-12)=0
We add all the numbers together, and all the variables
10x^2+23x+12=0
a = 10; b = 23; c = +12;
Δ = b2-4ac
Δ = 232-4·10·12
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-7}{2*10}=\frac{-30}{20} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+7}{2*10}=\frac{-16}{20} =-4/5 $
| 8x+1/6=1/3(1/2+9x)+5x | | 12x/6=13(1/6) | | 12x/6=13{1/6} | | 2^x2*0.25^x=8 | | (a-1)/3-(a-2)/4=1 | | 12x/6=13+1/6 | | 12x/6=13*1/6 | | 7x/8=9 | | X+(2×y)=402 | | 12x/6=131/6 | | 2y+4=-2y-1+7 | | 1/2+(x+2)^2=x(x-1) | | v-33=7 | | 1/2+(x+2)*2=x(x-1) | | 33x=32x–4 | | 1/2+(x+2)2=x(x-1) | | 20000-0.05x=2000 | | (50-2x)(40-2x)(X)=0 | | V²+9v+14=0 | | 26=6x+10 | | 3(8-y=-(y-4) | | A+5/3=a-5/2 | | X=4/5(x-8) | | 1/16=4^n | | 6(x+2)=4(9-X) | | 3/4z+1/2z+6=5 | | 1.8=x100= | | x4=-9x2 | | 8=5^b | | 6-4a=42 | | 7x-x.2x=1 | | 20+r=72 |